(1+2分之1²-2²)(2+3分之2²-3²).(99+100分之99²-100²)
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/27 11:55:53
![(1+2分之1²-2²)(2+3分之2²-3²).(99+100分之99²-100²)](/uploads/image/z/1170809-17-9.jpg?t=%281%2B2%E5%88%86%E4%B9%8B1%26%23178%3B-2%26%23178%3B%29%282%2B3%E5%88%86%E4%B9%8B2%26%23178%3B-3%26%23178%3B%29.%2899%2B100%E5%88%86%E4%B9%8B99%26%23178%3B-100%26%23178%3B%29)
(1+2分之1²-2²)(2+3分之2²-3²).(99+100分之99²-100²)
(1+2分之1²-2²)(2+3分之2²-3²).(99+100分之99²-100²)
(1+2分之1²-2²)(2+3分之2²-3²).(99+100分之99²-100²)
(1+2+·····+99)+ { 99 - [(1/2)² +(1/3)² +·····(1/100)² ] } - [(1²+2²+3²+····100²)-1] ,剩下的自己用数列公式计算,很简单的.