化简:[sin(2π-2)cos(π+x)tan(π-x)]/[cos(π-x)sin(3π-x)sin...化简:[sin(2π-2)cos(π+x)tan(π-x)]/[cos(π-x)sin(3π-x)sin(-π-x)]
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/27 12:10:22
![化简:[sin(2π-2)cos(π+x)tan(π-x)]/[cos(π-x)sin(3π-x)sin...化简:[sin(2π-2)cos(π+x)tan(π-x)]/[cos(π-x)sin(3π-x)sin(-π-x)]](/uploads/image/z/11644764-60-4.jpg?t=%E5%8C%96%E7%AE%80%EF%BC%9A%5Bsin%EF%BC%882%CF%80%EF%BC%8D2%EF%BC%89cos%EF%BC%88%CF%80%EF%BC%8Bx%EF%BC%89tan%EF%BC%88%CF%80%EF%BC%8Dx%EF%BC%89%5D%2F%5Bcos%EF%BC%88%CF%80%EF%BC%8Dx%EF%BC%89sin%EF%BC%883%CF%80%EF%BC%8Dx%EF%BC%89sin...%E5%8C%96%E7%AE%80%EF%BC%9A%5Bsin%EF%BC%882%CF%80%EF%BC%8D2%EF%BC%89cos%EF%BC%88%CF%80%EF%BC%8Bx%EF%BC%89tan%EF%BC%88%CF%80%EF%BC%8Dx%EF%BC%89%5D%2F%5Bcos%EF%BC%88%CF%80%EF%BC%8Dx%EF%BC%89sin%EF%BC%883%CF%80%EF%BC%8Dx%EF%BC%89sin%EF%BC%88%EF%BC%8D%CF%80%EF%BC%8Dx%EF%BC%89%5D)
化简:[sin(2π-2)cos(π+x)tan(π-x)]/[cos(π-x)sin(3π-x)sin...化简:[sin(2π-2)cos(π+x)tan(π-x)]/[cos(π-x)sin(3π-x)sin(-π-x)]
化简:[sin(2π-2)cos(π+x)tan(π-x)]/[cos(π-x)sin(3π-x)sin...
化简:
[sin(2π-2)cos(π+x)tan(π-x)]/[cos(π-x)sin(3π-x)sin(-π-x)]
化简:[sin(2π-2)cos(π+x)tan(π-x)]/[cos(π-x)sin(3π-x)sin...化简:[sin(2π-2)cos(π+x)tan(π-x)]/[cos(π-x)sin(3π-x)sin(-π-x)]
式子中的sin(2π-2)应该是sin(2π-x)吧!
[sin(2π-x)cos(π+x)tan(π-x)]/[cos(π-x)sin(3π-x)sin(-π-x)]
=[sin(2π-x)cos(π+x)tan(π-x)]/[cos(π-x)sin(3π-x)sin(-π-x)]
=[sin(-x)(-cosx)(-tanx)]/[-cosxsin(π-x)sin(π-x)]
=(-sinx*cosx*tanx)/(-cosx*sinx*sinx)
=tanx/sinx
=1/cosx