已知|x+5|与(x+2y-3)^2互为相反数,则x= y=
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![已知|x+5|与(x+2y-3)^2互为相反数,则x= y=](/uploads/image/z/11600996-68-6.jpg?t=%E5%B7%B2%E7%9F%A5%7Cx%2B5%7C%E4%B8%8E%28x%2B2y-3%29%5E2%E4%BA%92%E4%B8%BA%E7%9B%B8%E5%8F%8D%E6%95%B0%2C%E5%88%99x%3D+y%3D)
已知|x+5|与(x+2y-3)^2互为相反数,则x= y=
已知|x+5|与(x+2y-3)^2互为相反数,则x= y=
已知|x+5|与(x+2y-3)^2互为相反数,则x= y=
|x+5|与(x+2y-3)^2互为相反数
且他们本身都大于等于0 要互为相反数 只能他们都为0
所以x+5=0
x=-5
x+2y-3=0
所以y=4
|x+5|=0,则x=-5
(x+2y-3)^2=0,则x+2y=3,y=4
x=-5,y=4