c语言小代码,for循环,1+2+3+4的和下面的++i,为什么不能写成i+1?我要实现1+3+5+7的话怎么写?# include int main(void){\x09int i,sum = 0;\x09\x09for (i=1; i
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![c语言小代码,for循环,1+2+3+4的和下面的++i,为什么不能写成i+1?我要实现1+3+5+7的话怎么写?# include int main(void){\x09int i,sum = 0;\x09\x09for (i=1; i](/uploads/image/z/11449608-24-8.jpg?t=c%E8%AF%AD%E8%A8%80%E5%B0%8F%E4%BB%A3%E7%A0%81%2Cfor%E5%BE%AA%E7%8E%AF%2C1%2B2%2B3%2B4%E7%9A%84%E5%92%8C%E4%B8%8B%E9%9D%A2%E7%9A%84%2B%2Bi%2C%E4%B8%BA%E4%BB%80%E4%B9%88%E4%B8%8D%E8%83%BD%E5%86%99%E6%88%90i%2B1%3F%E6%88%91%E8%A6%81%E5%AE%9E%E7%8E%B01%2B3%2B5%2B7%E7%9A%84%E8%AF%9D%E6%80%8E%E4%B9%88%E5%86%99%3F%23+include+int+main%28void%29%7B%5Cx09int+i%2Csum+%3D+0%3B%5Cx09%5Cx09for+%28i%3D1%3B+i)
c语言小代码,for循环,1+2+3+4的和下面的++i,为什么不能写成i+1?我要实现1+3+5+7的话怎么写?# include int main(void){\x09int i,sum = 0;\x09\x09for (i=1; i
c语言小代码,for循环,1+2+3+4的和
下面的++i,为什么不能写成i+1?
我要实现1+3+5+7的话怎么写?
# include
int main(void)
{
\x09int i,sum = 0;
\x09
\x09for (i=1; i
c语言小代码,for循环,1+2+3+4的和下面的++i,为什么不能写成i+1?我要实现1+3+5+7的话怎么写?# include int main(void){\x09int i,sum = 0;\x09\x09for (i=1; i
# include <stdio.h>
int main(void)
{
int i, sum = 0;
for (i=1; i<=7; i+=2)//<----------
{
sum = sum+i;
printf("sum = %d\n", sum);
printf("i = %d\n\n", i);
}
printf("sum = %d\n\a", sum);
return 0;
}