求y=log2[2sin(π/3-2x)]的单调区间.请有才之人写出具体的步骤,我要最具体的步骤,
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![求y=log2[2sin(π/3-2x)]的单调区间.请有才之人写出具体的步骤,我要最具体的步骤,](/uploads/image/z/10757321-17-1.jpg?t=%E6%B1%82y%3Dlog2%5B2sin%EF%BC%88%CF%80%2F3-2x%EF%BC%89%5D%E7%9A%84%E5%8D%95%E8%B0%83%E5%8C%BA%E9%97%B4.%E8%AF%B7%E6%9C%89%E6%89%8D%E4%B9%8B%E4%BA%BA%E5%86%99%E5%87%BA%E5%85%B7%E4%BD%93%E7%9A%84%E6%AD%A5%E9%AA%A4%2C%E6%88%91%E8%A6%81%E6%9C%80%E5%85%B7%E4%BD%93%E7%9A%84%E6%AD%A5%E9%AA%A4%2C)
求y=log2[2sin(π/3-2x)]的单调区间.请有才之人写出具体的步骤,我要最具体的步骤,
求y=log2[2sin(π/3-2x)]的单调区间.
请有才之人写出具体的步骤,我要最具体的步骤,
求y=log2[2sin(π/3-2x)]的单调区间.请有才之人写出具体的步骤,我要最具体的步骤,
因为log2X是单调递增函数,所以只需要求2sin[(π/3-2x)]的单调区间 sinx的单调递增区间是(-π/2+2kπ,π/2+2kπ)单调递增在(π/2+2kπ,3π/2+2kπ)上递减 那么可算2sin[(π/3-2x)]得单调递增区间是-π/2+2kπ