(2/3xy)^-2÷(1/3x^-2)化成只含有正整数指数幂的形式
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![(2/3xy)^-2÷(1/3x^-2)化成只含有正整数指数幂的形式](/uploads/image/z/10451163-3-3.jpg?t=%282%2F3xy%29%5E-2%C3%B7%EF%BC%881%2F3x%5E-2%29%E5%8C%96%E6%88%90%E5%8F%AA%E5%90%AB%E6%9C%89%E6%AD%A3%E6%95%B4%E6%95%B0%E6%8C%87%E6%95%B0%E5%B9%82%E7%9A%84%E5%BD%A2%E5%BC%8F)
(2/3xy)^-2÷(1/3x^-2)化成只含有正整数指数幂的形式
(2/3xy)^-2÷(1/3x^-2)化成只含有正整数指数幂的形式
(2/3xy)^-2÷(1/3x^-2)化成只含有正整数指数幂的形式
(2/3xy)^-2÷(1/3x^-2)
=(9/4 x^-2y^-2)÷1/3x^-2
=27/4y²
3xy(x^2-xy^2+xy)-xy^2(2x^2-xy+2x)
1-(3xy-x)+【-2(2x+3xy)】
计算3xy[2xy-x(y-2)+x-1]
3xy^2-(XY^2-2X^2Y)÷(1/2xy)
(3x²y-xy²+1/2xy)÷(-1/2xy)
(3x²y-xy²+1/2xy)÷(-1/2xy)
①(9x²y-6xy²)÷3xy ②(3x²y-xy²+2分之1xy)÷(-2分之1xy)
因式分解X^3-2xy+xy^2
2xy.(-3xy)÷(xy)
2x²y-3(2xy-xy)-xy
(-3xy+2xy)-(4xy+xy)
(-1/3xy)^2•[xy(2x-y)-2x(xy-y^2)]
xy(xy+1)+xy+3-2(x+y+1/2)-(x+y-1)^2因式分解
(-3分之1xy)的平方×[xy(2x-y)-2x(xy-y的平方)]
XY(XY+3)+(XY+4)+4(X+Y+1)-(X+Y+2)
(-xy^-1)^2*(-xy^-2)^-3/(-x^2y^3)
( )-(x^2+3xy)=-xy-1/3y^2
y^3+xy^2+2xy+x^2-1 因式分解