已知x^m=9,x^n=6,x^k=4,求x^m-2n+2k
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![已知x^m=9,x^n=6,x^k=4,求x^m-2n+2k](/uploads/image/z/10398639-39-9.jpg?t=%E5%B7%B2%E7%9F%A5x%5Em%3D9%2Cx%5En%3D6%2Cx%5Ek%3D4%2C%E6%B1%82x%5Em-2n%2B2k)
已知x^m=9,x^n=6,x^k=4,求x^m-2n+2k
已知x^m=9,x^n=6,x^k=4,求x^m-2n+2k
已知x^m=9,x^n=6,x^k=4,求x^m-2n+2k
x^(m-2n+2k)=x^m/(x^n)^2*(x^k)^2=9/36*16=4
原式=x∧(m-2n+2k)
=(x∧m)/x∧(2n+2k)
=(x∧m)/[x∧(n+k)]∧2
∵x∧n=6,x∧k=4
∴x∧n*x∧k=x∧(n+k)=24
带入上式得
原式=9/24∧2
=1/64