(x+y+z)³+(3x-2y-3z)³-(4x-y-2z)³分解因式分了他,
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![(x+y+z)³+(3x-2y-3z)³-(4x-y-2z)³分解因式分了他,](/uploads/image/z/1025050-58-0.jpg?t=%EF%BC%88x%2By%2Bz%EF%BC%89%26%23179%3B%2B%EF%BC%883x-2y-3z%EF%BC%89%26%23179%3B-%EF%BC%884x-y-2z%EF%BC%89%26%23179%3B%E5%88%86%E8%A7%A3%E5%9B%A0%E5%BC%8F%E5%88%86%E4%BA%86%E4%BB%96%2C)
(x+y+z)³+(3x-2y-3z)³-(4x-y-2z)³分解因式分了他,
(x+y+z)³+(3x-2y-3z)³-(4x-y-2z)³分解因式
分了他,
(x+y+z)³+(3x-2y-3z)³-(4x-y-2z)³分解因式分了他,
(x+y+z)3+(3x-2y-3z)3-(4x-y-2z)3
=(4x-y-2z)[(x+y+z)^2-2(x+y+z)(3x-2y-3z)+(3x-2y-3z)^2]-(4x-y-2z)3
=(4x-y-2z)[(x+y+z)^2-2(x+y+z)(3x-2y-3z)+(3x-2y-3z)^2-(4x-y-2z)^2]
=(4x-y-2z)[(x+y+z)((x+y+z)-(3x-2y-3z))+((3x-2y-3z)-(4x-y-2z))((3x-2y-3z)+(4x-y-2z))]
=(4x-y-2z)[(x+y+z)(-2x+3y+4z)+(-x-y-z)(7x-3y-5z)]
=(4x-y-2z)(x+y+z)[(-2x+3y+4z)-(7x-3y-5z)]
=(4x-y-2z)(x+y+z)(-9x+6y+9z)
=3(4x-y-2z)(x+y+z)(-3x+2y+3z)
把最后一个"(4x-y-2z)"拆成(x+y+z) +(3x-2y-3z)两项的和(x+y+z)=a (3x-2y-3z)=b 原始的化为a3+b3-(a+b)3 剩下的我就不算了 你懂的
(x+y+z)3+(3x-2y-3z)3-(4x-y-2z)3
=(4x-y-2z)[(x+y+z)^2-2(x+y+z)(3x-2y-3z)+(3x-2y-3z)^2]-(4x-y-2z)3
=(4x-y-2z)[(x+y+z)^2-2(x+y+z)(3x-2y-3z)+(3x-2y-3z)^2-(4x-y-2z)^2]
=(4x-y-2z)[(x+y+z)((x+y+z)-(3x-2y-3z))+((3x-2y-3z)-(4x-y-2z))((3x-2y-3z)+(4x-y-2z))]
=(4x-y-2z)[(x+y+z)(-2x+3y+4z)+(-x-y-z)(7x-3y-5z)]
=(4x-y-2z)(x+y+z)[(-2x+3y+4z)-(7x-3y-5z)]
=(4x-y-2z)(x+y+z)(-9x+6y+9z)
=3(4x-y-2z)(x+y+z)(-3x+2y+3z)