已知a-b=1,a²+b²=13,求(a三次方-2*b三次方)-(a²b-2ab²)-(ab²-b三次方)的值
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![已知a-b=1,a²+b²=13,求(a三次方-2*b三次方)-(a²b-2ab²)-(ab²-b三次方)的值](/uploads/image/z/1023517-37-7.jpg?t=%E5%B7%B2%E7%9F%A5a-b%3D1%2Ca%26%23178%3B%2Bb%26%23178%3B%3D13%2C%E6%B1%82%28a%E4%B8%89%E6%AC%A1%E6%96%B9-2%2Ab%E4%B8%89%E6%AC%A1%E6%96%B9%29-%28a%26%23178%3Bb-2ab%26%23178%3B%29-%28ab%26%23178%3B-b%E4%B8%89%E6%AC%A1%E6%96%B9%EF%BC%89%E7%9A%84%E5%80%BC)
已知a-b=1,a²+b²=13,求(a三次方-2*b三次方)-(a²b-2ab²)-(ab²-b三次方)的值
已知a-b=1,a²+b²=13,求(a三次方-2*b三次方)-(a²b-2ab²)-(ab²-b三次方)的值
已知a-b=1,a²+b²=13,求(a三次方-2*b三次方)-(a²b-2ab²)-(ab²-b三次方)的值
原式=a³-2b³-a²b+2ab²-ab²+b³
=a³-a²b+ab²-b²
=a²(a-b)+b²(a-b)
=(a-b)(a²+b²)
=1×13
=13