若﹙2x+y-1﹚²+|x-2y-3|=0,求代数式﹙2x+y﹚﹙2x-y﹚-﹙x+2y﹚﹙x-2y-1)的值
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![若﹙2x+y-1﹚²+|x-2y-3|=0,求代数式﹙2x+y﹚﹙2x-y﹚-﹙x+2y﹚﹙x-2y-1)的值](/uploads/image/z/1022224-40-4.jpg?t=%E8%8B%A5%EF%B9%992x%2By-1%EF%B9%9A%26%23178%3B%2B%EF%BD%9Cx-2y-3%EF%BD%9C%3D0%2C%E6%B1%82%E4%BB%A3%E6%95%B0%E5%BC%8F%EF%B9%992x%2By%EF%B9%9A%EF%B9%992x-y%EF%B9%9A-%EF%B9%99x%2B2y%EF%B9%9A%EF%B9%99x-2y-1%EF%BC%89%E7%9A%84%E5%80%BC)
若﹙2x+y-1﹚²+|x-2y-3|=0,求代数式﹙2x+y﹚﹙2x-y﹚-﹙x+2y﹚﹙x-2y-1)的值
若﹙2x+y-1﹚²+|x-2y-3|=0,求代数式﹙2x+y﹚﹙2x-y﹚-﹙x+2y﹚﹙x-2y-1)的值
若﹙2x+y-1﹚²+|x-2y-3|=0,求代数式﹙2x+y﹚﹙2x-y﹚-﹙x+2y﹚﹙x-2y-1)的值
﹙2x+y-1﹚²+|x-2y-3|=0
∴﹛2x+y-1=0
x-2y-3=0
∴2x+y=1
x-2y=3
解得x=1,y=-1
∴﹙2x+y﹚﹙2x-y﹚-﹙x+2y﹚﹙x-2y-1)
=2x-y-(x+2y)×(3-1)
=2x-y-2x-4y
=-5y
=5