关于圆的标准方程1,若圆C的半径为1,圆心在第一象限,且与直线4x-3y=0和x轴都相切,则该圆的标准方程是( )A.(x-3)^2+[y-(7/3)]^2=1B.(x-2)^2+(y-1)^2=1C.(x-1)^2+(y-3)^2=1D.[x-(1/2)]^2+(y-1)^2=12,设P(x,y)是圆x^2+(y+4)^2=4
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![关于圆的标准方程1,若圆C的半径为1,圆心在第一象限,且与直线4x-3y=0和x轴都相切,则该圆的标准方程是( )A.(x-3)^2+[y-(7/3)]^2=1B.(x-2)^2+(y-1)^2=1C.(x-1)^2+(y-3)^2=1D.[x-(1/2)]^2+(y-1)^2=12,设P(x,y)是圆x^2+(y+4)^2=4](/uploads/image/z/10182654-54-4.jpg?t=%E5%85%B3%E4%BA%8E%E5%9C%86%E7%9A%84%E6%A0%87%E5%87%86%E6%96%B9%E7%A8%8B1%2C%E8%8B%A5%E5%9C%86C%E7%9A%84%E5%8D%8A%E5%BE%84%E4%B8%BA1%2C%E5%9C%86%E5%BF%83%E5%9C%A8%E7%AC%AC%E4%B8%80%E8%B1%A1%E9%99%90%2C%E4%B8%94%E4%B8%8E%E7%9B%B4%E7%BA%BF4x-3y%3D0%E5%92%8Cx%E8%BD%B4%E9%83%BD%E7%9B%B8%E5%88%87%2C%E5%88%99%E8%AF%A5%E5%9C%86%E7%9A%84%E6%A0%87%E5%87%86%E6%96%B9%E7%A8%8B%E6%98%AF%28+%29A.%28x-3%29%5E2%2B%5By-%287%2F3%29%5D%5E2%3D1B.%28x-2%29%5E2%2B%28y-1%29%5E2%3D1C.%28x-1%29%5E2%2B%28y-3%29%5E2%3D1D.%5Bx-%281%2F2%29%5D%5E2%2B%28y-1%29%5E2%3D12%2C%E8%AE%BEP%28x%2Cy%29%E6%98%AF%E5%9C%86x%5E2%2B%28y%2B4%29%5E2%3D4)
关于圆的标准方程1,若圆C的半径为1,圆心在第一象限,且与直线4x-3y=0和x轴都相切,则该圆的标准方程是( )A.(x-3)^2+[y-(7/3)]^2=1B.(x-2)^2+(y-1)^2=1C.(x-1)^2+(y-3)^2=1D.[x-(1/2)]^2+(y-1)^2=12,设P(x,y)是圆x^2+(y+4)^2=4
关于圆的标准方程
1,若圆C的半径为1,圆心在第一象限,且与直线4x-3y=0和x轴都相切,则该圆的标准方程是( )
A.(x-3)^2+[y-(7/3)]^2=1
B.(x-2)^2+(y-1)^2=1
C.(x-1)^2+(y-3)^2=1
D.[x-(1/2)]^2+(y-1)^2=1
2,设P(x,y)是圆x^2+(y+4)^2=4上任意一点,则√[(x-1)^2+(y-1)^2]的最大值为( )
A.√26+2 B.√26 C.5 D.6
3,已知集合A={(x,y)|x=3a+1,y=4a},集合B={(x,y)|(x-2)^2+y^2
关于圆的标准方程1,若圆C的半径为1,圆心在第一象限,且与直线4x-3y=0和x轴都相切,则该圆的标准方程是( )A.(x-3)^2+[y-(7/3)]^2=1B.(x-2)^2+(y-1)^2=1C.(x-1)^2+(y-3)^2=1D.[x-(1/2)]^2+(y-1)^2=12,设P(x,y)是圆x^2+(y+4)^2=4
1.利用图像可知:圆心纵坐标是1,从而答案为:B或D
由横坐标比纵坐标长,故选B
2.圆上一点(x,y)到点(1,1)的距离是切线段长度为最大值√(26-2^2)=√22(没有此答案)
3.点(x,y)到(x-2)^2+y^2=25a^2的圆心(2,0)距离小于5a,
√[(3a+1-2)^2+(4a-0)^2]1/6